Recursion method converts an integer n into a string
mission details
Use recursion to convert an integer n into a string, and then output it. When outputting, each character is required to be separated by a space. For example, if you enter 483, the string "4 8 3" should be output. The number of digits of n is uncertain and can be an integer of any number of digits.
Problem solving tips
1) If it is a negative number, convert it to a positive number, and artificially output a "-" sign.
2) You can use putchar(n%10+'0') or putchar(n%10+48) to output a character.
3) You can use putchar(32) to output a space.
AC code
#include<stdio.h>
void figureTrasform(int n){
//在此写入函数体
/*****************Begin******************/
if(n < 0){
n = -n;
putchar('-');
putchar(32);
}
if(n / 10) figureTrasform(n / 10);
putchar(n % 10 + 48);
putchar(32);
/***************** End ******************/
}
//注意主函数以在题目中给出
int main(){
long n;
scanf("%d", &n);
if(n==0){
//如果输入的n是0,则输出‘0’,结束。
putchar('0');
return 0;
}
figureTrasform(n); //调用数字转换函数
return 0;
}
Note: Recursive functions are easier to understand backwards