Python find out the index of an element in a two-dimensional array, custom function

#函数:找出二维数组中某个元素的索引
#功能:返回目标元素在原数组中出现位置的所有索引号
def found(List,AimList):#List:搜索数组,AimList:目标元素
    print('原来的数组是:')
    print(List)
    print('目标数组是:')
    print(AimList)
    num=[]
    i=0
    length=len(List)
    while i<length:
        if List[i]==AimList:
            num.append(i)
        i=i+1
    print('目标元素的索引是:')
    print(num)

x=[[1,2],[2,3],[1,2],[3,4],[1,2]]
AimInx=[1,2]
found(x,AimInx)

Output:

原来的数组是:
[[1, 2], [2, 3], [1, 2], [3, 4], [1, 2]]
目标数组是:
[1, 2]
目标元素的索引是:
[0, 2, 4]

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Origin blog.csdn.net/qq_43511299/article/details/114237686