Exercise 4-3 Find the sum of the simple interleaved sequence part of the given precision (15 points)
This question requires writing a program to calculate the sequence part of the sum 1-1/4 + 1/7-1/10 +… until the absolute value of the last item is not Greater than the given precision eps.
Input format:
Input a positive real number eps in one line.
Output format:
Output the partial sum value S in the format of "sum = S" in one line, accurate to six decimal places. The title guarantees that the calculation result does not exceed the double precision range.
Input example 1:
4E-2
Output example 1:
sum = 0.854457
Input example 2:
0.02
Output example 2:
sum = 0.826310
#include<stdio.h>
int main()
{
int i=1;
double eps,sum=0.0;
scanf("%lf",&eps);
while(1.0/(3*i-2)>eps)
{
if(i%2==1)
sum+=1.0/(3*i-2);
else
sum-=1.0/(3*i-2);
i++;
}
if(i%2==1)
sum+=1.0/(3*i-2);
else
sum-=1.0/(3*i-2);
printf("sum = %.6lf",sum);
}