tp5 image file upload
Select the picture, display the picture, and store it;
html part
<!doctype html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport"
content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<script src="/static/js/jquery.js" type="text/javascript" charset="utf-8"></script>
<title>上传图片</title>
</head>
<body>
<h2>tp5图片上传</h2>
<form id="form">
<input type="file" id="image" name="image" onchange="picture(this);" />
<img class="img">
</form>
</body>
<script type="text/javascript">
function picture() {
var datas = new FormData($('#form')[0]);
console.log(datas);
$.ajax({
url:"/index/index/img",
type:'POST',
data:datas,
dataType:'json',
cache:false,
processData:false,
contentType:false,
success: function(data) {
console.log(data);
$('.img').attr("src",""+data+"");
},
});
}
</script>
</html>
public function img()
{
$file = request()->file('image');//获取图片
$info = $file->move(ROOT_PATH . 'public' . DS . 'uploads');//图片存储
if($info){
$a= $info->getSaveName();
$b='/uploads/'.$a;
return $b;
}
}
A simple small function to upload pictures, but I did not write data storage.
Please enlighten me a lot! ! ! !