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topic
832. Flip the image
Given a binary matrix A, we want to flip the image horizontally first, then invert the image and return the result.
To flip a picture horizontally is to flip each line of the picture, that is, reverse the order. For example, the result of horizontally flipping [1, 1, 0] is [0, 1, 1].
Inverting the picture means that all 0s in the picture are replaced by 1s, and all 1s are replaced by 0s. For example, the result of reversing [0, 1, 1] is [1, 0, 0].
Example 1:
输入：[[1,1,0],[1,0,1],[0,0,0]]
输出：[[1,0,0],[0,1,0],[1,1,1]]
解释：首先翻转每一行: [[0,1,1],[1,0,1],[0,0,0]]；
然后反转图片: [[1,0,0],[0,1,0],[1,1,1]]
Example 2:
输入：[[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
输出：[[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
解释：首先翻转每一行: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]；
然后反转图片: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
prompt:
1 <= A.length = A[0].length <= 20
0 <= A[i][j] <= 1
Solution (Java)
Flip each line first, then invert the picture, change all 0s to 1, and 1 to 0.
class Solution
{
public int[][] flipAndInvertImage(int[][] A)
{
//创建保存结果结果数组
int[][] result = new int[A.length][A[0].length];
//翻转每一行
for(int index = 0;index < A.length;index++)
{
int colIndex = 0;
for(int scan = A[index].length - 1;scan >= 0;scan--)
{
result[index][colIndex++] = A[index][scan];
}
}
//反转图片
for(int index = 0;index < result.length;index++)
{
for(int scan = 0;scan < result[index].length;scan++)
{
if(result[index][scan] == 0)
{
result[index][scan] = 1;
}
else if(result[index][scan] == 1)
{
result[index][scan] = 0;
}
}
}
return result;
}
}