TP5 sorts and records the query result set

Requirements: need to check account table each account in report_date association table in which the month field order_num and bi_ci_fee and the record of (a list query can be successful because the problem did not find a little bit small, but unfortunately demolished Open writing, for viewing only)

account table

id	admin_id	channel	account	name	addtime
1	1001	PAIC	zhangsan	Zhang San	2021-03-01 00:00:00
2	1002	CPIC	lysis	Li Si	2021-03-01 00:00:00
3	1003	PICC	wangwu	Wang Wu	2021-03-01 00:00:00

system_user表

id	nick
1001	zhangsss
1002	lisii
1003	wangww

report_date表

id	account_id	order_date	bi_ci_fee	order_num	addtime
1	1	2021-03-01	2222.00	15	2021-03-01 00:00:00
2	2	2021-03-01	2500.00	18	2021-03-01 00:00:00
3	3	2021-03-01	3888.00	12	2021-03-01 00:00:00

>  先查询出所有的 account  账户    再遍历根据 id/account_id 在 report_date 查询 该月记录
>  account 的 admin_id 关联 system_user 的 id 联表查询只为得到 nick  

  $accounts = Db::table("account ")->alias("a")
            ->join("system_user u", "u.id=a.admin_id")
            ->field("a.name,a.id as account_id,u.nick as team_name")
            ->group("name")
            ->where("a.admin_id >0")
            ->select();

>  遍历account账户  根据每条account 的 name 来查询 并且 groupby name  
>  因为有 同一个姓名但是有多个 account 账户的.... 所以 根据 name  求 sum

  $last_month = date("Y-m", strtotime("-1 month"));  //求上个月的数据

  foreach ($accounts as $key => &$account) {
    
    
            $account['order_num'] = Db::table("tm_order_report_date")->alias("ord")
                ->Join("tm_account a ", "ord.account_id=a.id")
                ->where(['a.name' => $account['name']])
                ->where('order_date', 'like', '%' . $last_month . '%')
                ->sum("order_num");
            $account['total_bi_ci_fee'] = 
            number_format(Db::table("tm_order_report_date")->alias("ord")
            ->Join("tm_account a ", "ord.account_id=a.id anda.name='{
      
      $account['name']}'")
            ->where('order_date', 'like', '%' . $last_month . '%')
            ->sum("bi_ci_fee"), 2);
        }

>  这样就取到了需要 数据  但是  没有排序   我们需要按照 total_bi_ci_fee 来排序
>  排序方法    底部原文链接 https://blog.csdn.net/lz0426001/article/details/40784109

	/**
	 * 对查询结果集进行排序
	 * @access public
	 * @param array $list 查询结果
	 * @param string $field 排序的字段名
	 * @param array $sortby 排序类型
	 * asc正向排序 desc逆向排序 nat自然排序
	 * @return array
	 */
	function list_sort_by($list, $field, $sortby = 'asc') {
    
    
	    if (is_array($list)) {
    
    
	        $refer = $resultSet = array();
	        foreach ($list as $i => $data)
	            $refer[$i] = &$data[$field];
	        switch ($sortby) {
    
    
	            case 'asc': // 正向排序
	                asort($refer);
	                break;
	            case 'desc':// 逆向排序
	                arsort($refer);
	                break;
	            case 'nat': // 自然排序
	                natcasesort($refer);
	                break;
	        }
	        foreach ($refer as $key => $val)
	            $resultSet[] = &$list[$key];
	        return $resultSet;
	    }
	    return false;
	}

> 调用下排序方法

	 $sortedAccounts = $this->list_sort_by($accounts, "total_bi_ci_fee", 'desc');

	 此方法用于  获取前面24条   将查询出来的数据拆分前面一部分
	 $sortedAccounts = array_slice($sortedAccounts, 0, 24);

to sum up

$last_month = date("Y-m", strtotime("-1 month"));  //求上个月的数据

Db::table("tm_account")->alias("a")
            ->leftJoin("tm_order_report_date d", "a.id=d.account_id")
            ->leftJoin("system_user su", "a.admin_id=su.id")
            ->field("a.name,su.email as team_name,sum(if(DATE_FORMAT(order_date,'%Y-%m')='{
      
      $last_month}',d.order_num,0)) as order_num,sum(if(DATE_FORMAT(order_date,'%Y-%m')='{
      
      $last_month}',d.bi_ci_fee,0)) as total_bi_ci_fee")
            ->group("a.name")
            ->order("total_bi_ci_fee desc")
            ->where("a.admin_id >0 and a.name is not null")
            ->limit(0,24)
            ->select();
            一条SQL语句就完事了   遍历毛线...    写联表查询要注意细节....

php sorts the query result set