Use the queue, before starting to join the queue, determine the current queue length as the number of nodes that need to be printed next
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
std::deque<TreeNode*> q;
if (root) q.push_back(root);
vector<vector<int>> res;
while (!q.empty()) {
int len = q.size();
vector<int> row;
for (int i = 0; i < len; ++i) {
root = q.front();
q.pop_front();
row.push_back(root->val);
if (root->left) q.push_back(root->left);
if (root->right) q.push_back(root->right);
}
res.push_back(row);
}
return res;
}
};