1550. There are three consecutive odd arrays
Give you an integer array arr, please judge whether there are three consecutive elements in the array that are all odd numbers: if it exists, please return true; otherwise, return false
Solution: The multiplication of three odd numbers is still odd, and the multiplication of arbitrary numbers and even numbers is still even
class Solution:
def threeConsecutiveOdds(self, arr: List[int]) -> bool:
for i in range(len(arr) - 2):
mut = arr[i] * arr[i+1] * arr[i+2]
if mut%2 != 0:
return(True)
return(False)