Find an integer, the number of binary 1s when stored in memory

Ideas:

• Since the int type occupies 4 bytes, the for loop performs 32 times
• num right shift and 1 phase and

Code:

import java.util.Scanner;
public class pra1214 {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        System.out.println("请输入一个整数:");
        int num=sc.nextInt();
        int count=0;
        for(int i=0;i<32;i++){
            if((1&(num>>i))==1){
                count++;
            }
        }
        System.out.println("num在内存中存储时二进制1的个数为："+count);
    }
}

Note: In the if statement, it cannot be written as num&(1<<i), so the result may be a number such as 1000, which is incorrect.