1382. Balance a Binary Search Tree
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> V;
void inOrder(TreeNode* root) {
if(!root) return ;
inOrder(root->left);
V.push_back(root->val);
inOrder(root->right);
}
TreeNode* balanceBST(int l, int r) {
if(l >= r) return NULL;
int mid = (l + r) / 2;
TreeNode* root = new TreeNode(V[mid]);
root->left = balanceBST(l, mid);
root->right = balanceBST(mid + 1, r);
return root;
}
TreeNode* balanceBST(TreeNode* root) {
inOrder(root);
return balanceBST(0, V.size());
}
};