The main points of selection sorting: find the smallest integer from the current unsorted integers, and put it at the end of the sorted list (note the two keywords: sorted and unsorted), that is, select the smallest value for sorting Put it to the left.
Contrast bubbling sorting: each comparison of bubbling sorting may be interactive , and each traversal of selective sorting only records the subscript with the smallest value of the current traversal , and only one exchange occurs after the traversal is completed.
Code and debugging results:
#include <iostream>
using namespace std;
void select_sort(int list[], int num)
{
int min_pos = 0; //每次循环最小数的位置
for (int i = 0; i < num - 1; i++)
{
min_pos = i;
for (int j = i + 1; j < num; j++)
{
if (list[min_pos] > list[j])
min_pos = j; //记录最小数值的下标
}
swap(list[i],list[min_pos]); //每次遍历只发生一次交换
}
}
int main()
{
int arr[10] = {1,2,0,6,9,3,5,8,4,7};
select_sort(arr,sizeof(arr)/sizeof(arr[0]));
for (int i = 0; i < sizeof(arr) / sizeof(arr[0]); i++)
cout << arr[i] << " ";
cout << endl << endl << endl << endl;
return 0;
}
Time complexity of selection sort:
Number of comparisons: (N-1) + (N-2)+ ... + 2 + 1 = ((N-1) + 1) *(N-1)/2 = N^2/2-N/ 2;
Number of exchanges: N-1
Therefore, the time complexity is: (N^2/2-N/2) + (N-1) = N^2/2+N/2-1
According to the Big O rule, the highest order term is retained, and the constant silver is taken out. The time complexity is O(N^2)