Find a specific number in an ordered array, suppose we find n
#include <stdio.h>
#include <stdlib.h>
int main()
{ int arr[] = {1, 2, 3, 4, 5, 6, 7, 8 }; int k = 7; int sz = sizeof(arr) / sizeof(arr[0]);//Calculate the number of elements int left = 0;//left subscript int right = sz-1;//right subscript while (left<=right) {
int mid = (left + right) / 2;
if (arr[mid] > k)
{
right = mid - 1;
}
else if (arr[mid] < k)
{
left = mid + 1;
}
else
{
printf("找到了,下标是:%d\n", mid);
break;
}
}
if (left>right)
{
printf("找不到\n");
}
system(“pause”);
return 0;
}