0211leetcode brushes 5 python questions

11

Title description:
Give you n non-negative integers a1, a2,..., an, each of which represents a point (i, ai) in the coordinates. Draw n vertical lines in the coordinates. The two end points of the vertical line i are (i, ai) and (i, 0) respectively. Find two of the lines so that the container that they form with the x-axis can hold the most water.

Example:
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Answer:

class Solution:
    def maxArea(self, height: List[int]) -> int:
        maxv=0
        i,j=0,len(height)-1
        while i<j:
            h=min(height[i],height[j])
            maxv=max(maxv,h*(j-i))
            if height[i]<height[j]:
                i+=1
            else:
                j-=1
        return maxv

21

Title description:
Combine two ascending linked lists into a new ascending linked list and return. The new linked list is composed by splicing all the nodes of the given two linked lists.

Example:
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Answer:

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode:
        res = ListNode(None)
        node = res
        while l1 and l2:
            if l1.val<l2.val:
                node.next,l1 = l1,l1.next
            else:
                node.next,l2 = l2,l2.next
            node = node.next
        if l1:
            node.next = l1
        else:
            node.next = l2
        return res.next  

76

Title description:
Give you a string s and a string t. Returns the smallest substring of s that covers all characters of t. If there is no substring in s that covers all characters of t, an empty string "" is returned.

Example:
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Answer:

class Solution:
    def minWindow(self, s: str, t: str) -> str:
        mem=defaultdict(int)
        for char in t:
            mem[char]+=1
        t_len=len(t)

        minLeft,minRight=0,len(s)
        left=0

        for right,char in enumerate(s):
            if mem[char]>0:
                t_len-=1
            mem[char]-=1

            if t_len==0:
                while mem[s[left]]<0:
                    mem[s[left]]+=1
                    left+=1

                if right-left<minRight-minLeft:
                    minLeft,minRight=left,right

                mem[s[left]]+=1
                t_len+=1
                left+=1
        return '' if minRight==len(s) else s[minLeft:minRight+1]

84

Title description:
Given n non-negative integers, they are used to represent the height of each column in the histogram. Each pillar is adjacent to each other and has a width of 1.
Find the maximum area of ​​the rectangle that can be outlined in the histogram.
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Example:
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Answer:

class Solution:
    def largestRectangleArea(self, heights: List[int]) -> int:
        '''
        超时
        res = 0
        n = len(heights)
        for i in range(n):
            left_i = i
            right_i = i
            while left_i >= 0 and heights[left_i] >= heights[i]:
                left_i -= 1
            while right_i < n and heights[right_i] >= heights[i]:
                right_i += 1
            res = max(res, (right_i - left_i - 1) * heights[i])
        return res
        '''
        #单调栈
        stack = []
        heights = [0] + heights + [0]
        res = 0
        for i in range(len(heights)):
            #print(stack)
            while stack and heights[stack[-1]] > heights[i]:
                tmp = stack.pop()
                res = max(res, (i - stack[-1] - 1) * heights[tmp])
            stack.append(i)
        return res

665

Title description:
Give you an integer array of length n. Please judge whether the array can become a non-decreasing sequence when one element is changed at most.
We define a non-decreasing number sequence like this: For all i (0 <= i <= n-2) in the array, nums[i] <= nums[i + 1] is always satisfied.

Example:
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Answer:

class Solution:
    def checkPossibility(self, nums: List[int]) -> bool:
        N = len(nums)
        count = 0
        for i in range(1, N):
            if nums[i] < nums[i - 1]:
                count += 1
                if i == 1 or nums[i] >= nums[i - 2]:
                    nums[i - 1] = nums[i]
                else:
                    nums[i] = nums[i - 1]
        return count <= 1

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Origin blog.csdn.net/yeqing1997/article/details/113715145