PAT Grade A-Base Conversion-1058 A+B in Hogwarts Problem Solving Ideas

1058 A+B in Hogwarts (20 分)

Ideas

The base conversion still has to look at the division and remainder.
There is a pit, carry, need to add carry item

Code

#include <bits/stdc++.h>
using namespace std;


int main()
{
    
    
    int in1[3];
    int in2[3];
    scanf("%d.%d.%d",&in1[0],&in1[1],&in1[2]);

    scanf("%d.%d.%d",&in2[0],&in2[1],&in2[2]);

    int out[3]={
    
    0};
    out[2] = (in1[2]+in2[2])%29;
    out[1] =  (in1[1]+in2[1]+(in1[2]+in2[2])/29)%17; #加上carry项
    out[0]= in1[0]+in2[0] + (in1[1]+in2[1]+(in1[2]+in2[2])/29)/17;

    printf("%d.%d.%d",out[0],out[1],out[2]);
    
}