Kotlin break continue to understand at a glance

 break

1 Double loop break outer loop

loopOne@ for (i in 1..10) {
        println("i ${i}")
        for (j in 1..10) {
            
            if (i == 2 && j == 8) break@loopOne
            print("j ${j}    ")

        }
        println()
    }

The output log is as follows:

2 Double loop break inner loop

for (i in 1..10) {
        println("i ${i}")
        loopTwo@ for (j in 1..10) {
           
            if (i == 2 && j == 8) break@loopTwo
            print("j ${j}    ")

        }
        println()
    }

 The output log is as follows:

It can be seen from the log that when only i==2 && j==8, the loop of j is interrupted by break, and then i == 3 and will continue to loop afterwards

continue 

 for (i in 1..10) {
        println("i ${i}")
        for (j in 1..10) {
            if (i == 2 && j == 8) continue
            print("j ${j}    ")
        }
        println()
    }

The output log is as follows:

It can be seen from the log that in this case only i==2 && j==8, it only stops this time, but will continue the subsequent cycle

 

to sum up:

1 break interrupt all subsequent cycles of the specified loop

2 continue Interrupt the current operation of the loop that meets the condition, and continue after this interruption

3 The code before the break/continue that meets the conditions will be executed, but the code after it will not be executed, as follows:

 for (i  in 1..100){
        //代码位置1
        if (i == 6) break/continue
        //代码位置2
    }

Code position 1 will be executed;   code position 2 will not be executed;