Little A and Little B are playing guessing numbers. Little B randomly chooses one from 1, 2, 3 each time, and Little A also
chooses one guess from 1, 2, 3 each time . They played this game three times in total. Please go back to Little A. How many times did you guess correctly?
The input guess array is the guess of small A each time, and the answer array is the choice of small B each time.
The length of guess and answer are both equal to 3.
Example 1:
Input: guess = [1,2,3], answer = [1,2,3]
Output: 3
Explanation: Little A guessed right every time.
Example 2:
Input: guess = [2,2,3], answer = [3,2,1]
Output: 1
Explanation: Little A only guessed correctly the second time.
Idea: The same number of elements in the guess and answer arrays with the same subscript
//方法1
int game1(int* guess, int guessSize, int* answer, int answerSize){
return(*guess==*answer)+(*++guess==*++answer)+(*++guess==*++answer);
}
//方法2
int game2(int* guess, int guessSize, int* answer, int answerSize)
{
int count = 0;//统计猜对的次数
for (int i = 0; i < guessSize; i++)
{
if (guess[i] == answer[i])//比较两个数组相同位置下的值是否相等
{
count++;
}
}
return count;
}
The running results on Likou correspond to method 1 and method 2 respectively
