response to jump

Create a servlet program, accept the request and respond to the redirected address
servlet program:

import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;

public class RedirectTest extends HttpServlet{
    
    
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws IOException {
    
    
        resp.sendRedirect("/index.jsp");
    }
    protected void doPost(HttpServletRequest req, HttpServletResponse resp){
    
    
    }
}

Register servlet in xml:

<!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app>
  <display-name>Archetype Created Web Application</display-name>
  <servlet>
    <servlet-name>redirect</servlet-name>
    <servlet-class>redriecttest.RedirectTest</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>redirect</servlet-name>
    <url-pattern>/rdctt</url-pattern>
  </servlet-mapping>
</web-app>

Guess you like

Origin blog.csdn.net/kitahiragawa/article/details/112026587