analysis:
Find the formula:
for iii包含a [i] a [i]a [ i ] Imaginary unit sharingi ∗ (n − i + 1) i * (n-i + 1)i∗(n−i+1 ) one of thea [i] a [i]a [ i ] Completion of calculationi ∗ (n − i + 1) i * (n-i + 1)i∗(n−i+1 ) times
lastaccumulateto
CODE:
#include<iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
const long long p=1e9+7;
long long n,x,ans;
int main(){
scanf("%lld",&n);
for(long long i=1;i<=n;i++)
{
scanf("%lld",&x);
ans=(ans+x*(i*(n-i+1)))%p; //累加 公式
}
printf("%lld",ans%p);
return 0;
}