How to express the array size in c language: sizeof(array)/sizeof(array[0])

 

#include <stdio.h>

int * find_largest(int *,int );

int main()
{
int array[] = {1,2,3,4,5,6,7,1004,5,1};
int *ptr = find_largest(array,sizeof(array,sizeof(array[0])));
printf("%d",*ptr);
return 0;
}


int * find_largest(int *a,int n)
{
int *largest = a,*p;
for( p = a; p != a+n;++p)
   {   
     if(*p > *largest)
        largest = p;
   }   
return largest;
}


                                                                             
              

The size of the array in the function parameters can be represented by: sizeof(array)/sizeof(array[0])

Guess you like

Origin blog.csdn.net/digitalkee/article/details/112061110
Recommended