Example 38: There are three candidates, and each voter can only vote for one person. It is required to compile a program for counting votes in C language, input the names of candidates one after another, and finally output the results of each person's votes.
Problem-solving idea: You need to design a structured array, which contains 3 elements, and the information in each element should include the candidate's name and the number of votes.
Source code demo:
#include<stdio.h>//头文件
#include<string.h>//引入strcmp
struct people//定义结构体变量
{
char name[20];//定义字符数组
int number;//定义整型变量
} leader[3]={
"li",0,"zhang",0,"sun",0}; /*数组的定义和引用不一样，把姓赋给数组name 把0赋给 shu*/
int main()//主函数
{
int i,j;//定义整型变量
char leader_name[20];//定义字符数组
for(i=1;i<10;i++)//for循环，循环9次
{
printf("请输入人名\n");//提示语句
scanf("%s",leader_name);//键盘输入名字
for(j=0;j<3;j++)
if(strcmp(leader_name,leader[j].name)==0)//比较两个字符串，如果名字相等
{
leader[j].number++;//票数加1
}
}
printf("结果是：\n");//提示语句
for(i=0;i<3;i++)//for循环
{
printf("%s票数：%d\n",leader[i].name,leader[i].number);//输出名字和票数
}
return 0;//主函数返回值为0
}
The compilation and running results are as follows:
请输入人名
li
请输入人名
zhang
请输入人名
sun
请输入人名
sun
请输入人名
li
请输入人名
li
请输入人名
li
请输入人名
sun
请输入人名
sun
结果是：
li票数：4
zhang票数：1
sun票数：4
--------------------------------
Process exited after 23.01 seconds with return value 0
请按任意键继续. . .
C language statistical voting results
More cases can go public account: C language entry to proficient