Exercise 3-5 Leap Year Output (15 points)
Output all leap years since the end of a certain year in the 21st century. Note: The judging condition for leap years is that the year of the year can be divisible by 4 but not by 100 or by 400.
Input format:
Enter a certain cut-off year for the 21st century in one line.
Output format:
output all leap year years that meet the conditions line by line, that is, each year occupies one line. If you input a year other than the 21st century, output "Invalid year!". If there is no leap year, output "None".
Input example 1:
2048
Output example 1:
2004
2008
2012
2016
2020
2024
2028
2032
2036
2040
2044
2048
Input example 2:
2000
Output example 2:
Invalid year!
Author
Chen Jianhai
Unit
Zhejiang University
Code length limit
16 KB
Time limit
400 ms
memory limit
64 MB
#include <stdio.h>
int main(void) {
int year = 0;
int count = 0;
if (scanf("%d", &year) == 1) {
if (2000 < year && year <= 2100) {
for (int i = 2001; i <= year; i++) {
if ((i % 4 == 0 && i % 100 != 0) || i % 400 == 0) {
printf("%d\n", i);
count++;
}
}
} else {
printf("Invalid year!");
}
if (count == 0 && 2000 < year && year < 2100) {
printf("None");
}
}
return 0;
}