C++ and python realize Armstrong number search

1. Title explanation

If an n-digit positive integer is equal to the sum of the n-th power of its digits, the number is called an Armstrong number. For example, 1^3 + 5^3 + 3^3 = 153 .
Armstrong numbers within 1000: 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407

2. Determine whether a number is an Armstrong number

1. First come with a simple code to determine whether a number is an Armstrong number ;
let’s take a look at the code written in C++

#include <iostream>
using namespace std;
int main()
{
    
    
	int n, r, sum=0, temp;  
	cout<<"Enter the Number=  ";  
	cin>>n;  
	temp=n;  
	while(n>0)  
	{
    
      
		r=n%10;  
		sum=sum+(r*r*r);  
		n=n/10;  
	}  
	if(temp==sum)  
		cout<<"Armstrong Number."<<endl;  
	else  
		cout<<"Not Armstrong Number."<<endl; 
	return 0;
}

operation result:

Next look at Python

num = int(input("请输入一个数字："))
sum= 0
n = len(str(num))
temp = num
while temp >0:
    digit = temp %10 # 获取个位数字
    sum += digit**n  # 对计算结果进行累加
    temp //= 10
if num == sum :
    print("太棒了！",num,"是阿姆斯特朗数")
else:
    print("很遗憾！",num,"不是阿姆斯特朗数")

operation result:

2. Write a search for Armstrong numbers in a fixed range

Python implementation:

lower = int(input("最小值："))
upper = int(input("最大值："))
print("下面是你想要从{}到{}之间的阿姆斯特朗数\n".format(lower,upper))
for num in range(lower,upper+1):
    sum = 0
    n = len(str(num))
    temp = num
    while temp >0:
        digit = temp %10 # 获取个位数字
        sum+= digit**n  # 对计算结果进行累加

        temp //= 10
    if num == sum:
        print(num)

Running results:

C++ implementation:

#include <iostream>
using namespace std;

int test(int a,int b,int c,int d)
{
    
    
	if(a)return a*a*a*a+b*b*b*b*b+c*c*c*c+d*d*d*d*d;
	if(b)return b*b*b+c*c*c+d*d*d;
	if(c)return c*c+d*d;
	if(d)return d;
}
void func(int min, int max)
{
    
    
	if(min<=0||min>=max||max<0||max>9999)
	{
    
    
		cout << "error!" << endl;
	}
	int a,b,c,d;
	for(int i=min;i<=max;i++)
	{
    
    
		a = i/1000;
		b = (i%1000)/100;
		c = (i%100)/10;
		d = i%10;
		if(i==test(a,b,c,d))
			cout << i << endl;
	}
}

int main()
{
    
    
	int min,max;
	cin >> min;
	cin >> max;

	func(min,max);

	system("pause");
	return 0;
}

Run results show:

C++ is too complicated to learn from python. What a friendly language, the second day after the burst of learning C++ mentality, if it helps, please pay attention to it!