Claim:
Output the character abdgdbcaethbganmugthaesqszaphfdvwdthat appears most frequently in a given string and count its times.
Realization ideas:
- Use to
charA()traverse this string - Store each character in the object, if the object does not have this attribute, the first amplitude is 1, and if it exists, it will be +1
- Traverse the object, get the maximum value and the character
- In the process of traversal, each character in the string is stored in the object as an attribute of the object, and the corresponding attribute value is the number of times the character appears
Code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<script>
// 1.统计次数
var str = 'abdgdbcaethbganmugthaesqszaphfdvwd';
var obj = {
};
// 创建了一个空的对象，存储字符串中的每个字符。属性：每个字符，属性值：该字符出现的次数
for (var i = 0; i < str.length; i++) {
// 遍历字符串
var chars = str.charAt(i);
// chars代表字符串的每一个字符
if (obj[chars]) {
obj[chars]++;
} else {
obj[chars] = 1;
}
// obj[chars]属性值：该字符出现的次数
// 如果已经存在，那么次数+1；否则赋值为1
}
console.log(obj);
// 输出对象obj，显示每个字符出现的次数
// 2.遍历对象，找出最大的次数
var max = 0;
var ch = '';
for (var k in obj) {
if (obj[k] > max) {
max = obj[k];
ch = k;
}
}
// k代表属性：每个字符
// obj[k]代表属性值：该字符出现的次数
// 将次数最多的字符赋值到ch
console.log('最多的字符是' + ch + '，次数为' + max);
</script>
</body>
</html>
Output result:
