pta Exercise 3-3 Count the average score and the number of passing students (15 points)

Topic Collection of Zhejiang University Edition "C Language Programming (3rd Edition)"

Exercise 3-3 Count the average score and the number of passing students (15 points)

This question requires writing a program to calculate the average grade of the students and count the number of passers (with a score of not less than 60 points). The question guarantees that the input and output are within the integer range.

Input format:

Enter a non-negative integer N in the first line, which is the number of students. The second line gives N non-negative integers, that is, the scores of these N students, separated by spaces.

Output format:

Output in the following format:

average = average score
count = number of passing

The average value is accurate to one decimal place.

Input sample:

5
77 54 92 73 60

Sample output:

average = 71.2
count = 4

Code:

#include <stdio.h>
#include <stdlib.h>

int main()
{
    
    
    int N;
    int count=0,sum=0;
    double P;
    scanf("%d\n",&N);
    for (int i=0; i<N; i++)
    {
    
    
        int a;
        scanf("%d",&a);
        if(a>=60)
        {
    
    
            count ++;
        }
        sum=sum+a;
    }
    P= N==0? 0: sum*1.0/N;
    printf("average = %.1f\n",P);
    printf("count = %d",count);
}

Submit result:

to sum up:

1. The ternary operator can be used to simplify the code, but in this question there must be a parameter to receive the result of the program, as shown below

         P= N==0? 0: sum*1.0/N;

The following method cannot be used directly, otherwise an error will occur.

         N==0? 0: sum*1.0/N;

2. Pay attention to the output format.