Realize various basic operations in the sequence string, and design a program on this basis to complete the following functions.
- Create the string s=”abcdefghefghijklmn” and the string s1=”xyz”
- Output string s
- The length of the output string s
- Insert string input string s1 at the 9th character position of string s to generate string s2
- Output string s2
- Delete the 5 characters starting from the second character of the string s to produce the string s2
- Output string s2
- Replace the 5 characters starting with the second character of string s with s1 to produce string s2
- Output string s2
- Extract 10 characters from the second character of string s to generate string s3
- Output string s3
- Connect string s1 and string s2 to produce string s4
- The output string s4
program is as follows
sqstring.cpp
//顺序串基本运算的算法
#include <stdio.h>
#define MaxSize 100
typedef struct
{
char data[MaxSize];
int length; //串长
} SqString;
void StrAssign(SqString &s,char cstr[]) //字符串常量赋给串s
{
int i;
for (i=0;cstr[i]!='\0';i++)
s.data[i]=cstr[i];
s.length=i;
}
void DestroyStr(SqString &s)
{
}
void StrCopy(SqString &s,SqString t) //串复制
{
int i;
for (i=0;i<t.length;i++)
s.data[i]=t.data[i];
s.length=t.length;
}
bool StrEqual(SqString s,SqString t) //判串相等
{
bool same=true;
int i;
if (s.length!=t.length) //长度不相等时返回0
same=false;
else
for (i=0;i<s.length;i++)
if (s.data[i]!=t.data[i]) //有一个对应字符不相同时返回0
{
same=false;
break;
}
return same;
}
int StrLength(SqString s) //求串长
{
return s.length;
}
SqString Concat(SqString s,SqString t) //串连接
{
SqString str;
int i;
str.length=s.length+t.length;
for (i=0;i<s.length;i++) //将s.data[0..s.length-1]复制到str
str.data[i]=s.data[i];
for (i=0;i<t.length;i++) //将t.data[0..t.length-1]复制到str
str.data[s.length+i]=t.data[i];
return str;
}
SqString SubStr(SqString s,int i,int j) //求子串
{
SqString str;
int k;
str.length=0;
if (i<=0 || i>s.length || j<0 || i+j-1>s.length)
return str; //参数不正确时返回空串
for (k=i-1;k<i+j-1;k++) //将s.data[i..i+j]复制到str
str.data[k-i+1]=s.data[k];
str.length=j;
return str;
}
SqString InsStr(SqString s1,int i,SqString s2) //插入串
{
int j;
SqString str;
str.length=0;
if (i<=0 || i>s1.length+1) //参数不正确时返回空串
return str;
for (j=0;j<i-1;j++) //将s1.data[0..i-2]复制到str
str.data[j]=s1.data[j];
for (j=0;j<s2.length;j++) //将s2.data[0..s2.length-1]复制到str
str.data[i+j-1]=s2.data[j];
for (j=i-1;j<s1.length;j++) //将s1.data[i-1..s1.length-1]复制到str
str.data[s2.length+j]=s1.data[j];
str.length=s1.length+s2.length;
return str;
}
SqString DelStr(SqString s,int i,int j) //串删去
{
int k;
SqString str;
str.length=0;
if (i<=0 || i>s.length || i+j>s.length+1) //参数不正确时返回空串
return str;
for (k=0;k<i-1;k++) //将s.data[0..i-2]复制到str
str.data[k]=s.data[k];
for (k=i+j-1;k<s.length;k++) //将s.data[i+j-1..s.length-1]复制到str
str.data[k-j]=s.data[k];
str.length=s.length-j;
return str;
}
SqString RepStr(SqString s,int i,int j,SqString t) //子串替换
{
int k;
SqString str;
str.length=0;
if (i<=0 || i>s.length || i+j-1>s.length) //参数不正确时返回空串
return str;
for (k=0;k<i-1;k++) //将s.data[0..i-2]复制到str
str.data[k]=s.data[k];
for (k=0;k<t.length;k++) //将t.data[0..t.length-1]复制到str
str.data[i+k-1]=t.data[k];
for (k=i+j-1;k<s.length;k++) //将s.data[i+j-1..s.length-1]复制到str
str.data[t.length+k-j]=s.data[k];
str.length=s.length-j+t.length;
return str;
}
void DispStr(SqString s) //输出串s
{
int i;
if (s.length>0)
{
for (i=0;i<s.length;i++)
printf("%c",s.data[i]);
printf("\n");
}
}
exp4-1.cpp
#include "sqstring.cpp"
void main()
{
SqString s,s1,s2,s3,s4;//建立串
printf("1) 建立串s=abcdefghefghijkmn,和串s1=xyz\n");
StrAssign(s,"abcdefghefghijklmn");//写入串
StrAssign(s1,"xyz");
printf("2) 输出串s:\n");
DispStr(s);
printf("3) 输出串s长度:%d\n",s.length);
StrLength(s);
printf("4)在串s的第9个字符位置插入串次输入串s1而产生串s2\n");
InsStr(s,9,s1);
s2=InsStr(s,9,s1);//这个步骤可以省略下面同理
printf("5)输出串s2\n");
DispStr(s2);
printf("6)删除串s的第2个字符开始的5个字符而产生串s2\n");
DelStr(s,2,5);
s2=DelStr(s,2,5);
printf("7)输出串s2\n");
DispStr(s2);
printf("8)将串s的第2个字符开始的5个字符替换成s1而产生串s2\n");
RepStr(s,2,5,s1);
s2=RepStr(s,2,5,s1);
printf("9)输出串s2\n");
DispStr(s2);
printf("10)提取串s的第2个字符开始的10个字符而产生串s3\n");
SubStr(s,2,10);
s3=SubStr(s,2,10);
printf("11)输出串s3\n");
DispStr(s3);
printf("12)将串s1和串s2连接起来而产生串s4\n");
Concat(s1,s2);
s4=Concat(s1,s2);
printf("13)输出串s4\n");
DispStr(s4);
}