7.9-Practice questions-choose structure and loop structure (input a batch of integers, input the largest and smallest, and end when the number 0 is entered)

Question 1: Enter a batch of integers, enter the largest and smallest, and end when the number 0 is entered.

Ideas:

  1. It ends when 0 is entered, then a do...while... loop is needed
  2. The first number is generated outside of the circulation, and the other number is min and max.
  3. Then compare each number generated in the loop with min and max. If it is less than min, it will be a new min, and if it is greater than max, it will be a new max, so as to bubble to produce the maximum and minimum values.
  4. But pay attention to exit when n==0, otherwise the minimum value is always 0.

code show as below:

public class tast5 {
    
    
    public static void main(String[] args) {
    
    
        Scanner sc = new Scanner(System.in);
        System.out.print("请输入一批整数:");
        int max = sc.nextInt();
        int min = max;

        do {
    
    
            System.out.print("请输入一批整数:");
            int n = sc.nextInt();
            if (n==0)
                break;
            if (n>max)
                max = n;
            if (n <min)
                min = n;


        }while (true);
        System.out.println("输入最大值:"+max);
        System.out.println("输入最大值:"+min);
    }
}

The results are as follows:

请输入一批整数:45
请输入一批整数:12
请输入一批整数:98
请输入一批整数:01
请输入一批整数:65
请输入一批整数:0
输入最大值:98
输入最大值:1

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Origin blog.csdn.net/qq_42005540/article/details/107224174