Algorithm: Leetcode.15. Sum of three numbers

Subject: https://leetcode-cn.com/problems/3sum/

Answer: double pointer

 public List<List<Integer>> threeSum(int[] nums) {

     Arrays.sort(nums);

        int len = nums.length;

        List<List<Integer>> result = new ArrayList<>();

        for(int i=0;i<len;i++){

            if(i>0 && nums[i] == nums[i-1]){

                continue;

            }

            if(nums[i]>0) break;

            int right = len-1;

            int target = -nums[i];

            for(int left = i+1;left<len;left++){

                if(left>i+1 && nums[left] == nums[left-1]){

                    continue;

                }

                if(nums[i]+nums[left]>0) break;

                while (left<right && nums[left]+nums[right]>target){

                    right--;

                }

                if(left == right) break;

                if(nums[left] +nums[right] == target){

                    List<Integer> list = new ArrayList<>();

                    list.add(nums[i]);

                    list.add(nums[left]);

                    list.add(nums[right]);

                    result.add(list);

                }

            }

        }

        return result;

    }

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Origin blog.csdn.net/wuqiqi1992/article/details/108548897