describe
The program fills in the blanks to make it output 9 22 5
#include <iostream>
using namespace std;
class Sample {
public:
int v;
// 在此处补充你的代码
};
void PrintAndDouble(Sample o)
{
cout << o.v;
cout << endl;
}
int main()
{
Sample a(5);
Sample b = a;
PrintAndDouble(b);
Sample c = 20;
PrintAndDouble(c);
Sample d;
d = a;
cout << d.v;
return 0;
}
analysis:
- Observing several constructors, you will find that what you need are conversion constructors and copy constructors.
- Among them
d = a
is the default assignment operator, so it can be seen that a is 5 after the conversion constructor is created. So there is no change in the conversion constructor.- The b copy constructor takes a as the parameter, and then becomes 9. 5 becomes 9, because the parameter also needs to be copied to generate temporary variables, and the temporary variables are copied to b after the operation, so the two copies are equal to 4, so copy The constructor is plus 4.
- c is 22, 20 conversion constructor to generate a temporary object, and then copy to c, so one conversion and one copy are used.
years:
Sample(int i=0):v(i){
}
Sample(const Sample& s)
{
v=s.v+2;
}