topic:
Analysis: The largest number: 1. . . 1+0=1.. . . 1
20-6=14。14/2=7 7/2=3
At first, I was frightened. Think about it later, violently enumerate, count the number required for each number, and then enumerate it!
Code:
#include<bits/stdc++.h>
using namespace std;
int cnt[10]={
6,2,5,5,4,5,6,3,7,6};
int A[10000000];
int f_sum(int x)
{
if(A[x]!=-1) return A[x];
string s=to_string(x);
int sum=0;
for(int i=0;i<s.size();i++)
{
sum+=cnt[s[i]-'0'];
}
A[x]=sum;
return sum;
}
int main()
{
memset(A,-1,sizeof(A));
int m;
cin>>m;
m=m-4;
int ans=0;
for(int i=0;i<=1000;i++)
{
int a=i+i;
if(f_sum(i)+f_sum(i)+f_sum(a)==m) ans++;
for(int j=i+1;j<=1000;j++)
{
a=i+j;
if(f_sum(i)+f_sum(j)+f_sum(a)==m)
{
ans+=2;
}
}
}
cout<<ans;
}