Numerical method iterative method for solving nonlinear equations

Solve the nonlinear equation y = x ^ 3 + 4 * x ^ 2-10 at the root of the interval [1,2], accurate to the third decimal place. You
need to determine the equivalent equation yourself

#include <iostream>
#define WUCHA 0.0005
using namespace std;
double hanshu(double x) {//函数
    return 0.5 * sqrt((10 - x * x * x));
}
int main()
{
    double x = 1.5;
    double xx = 10000000;
    int count = 0;
    while (abs(x - xx) > WUCHA) {
        xx = x;
        x=hanshu(x);
        count++;
    }
    cout << "结果:" << x <<endl;
    cout << "迭代次数:" << count;
}