leecode-medium number

//中位数
#include <iostream>
using namespace std;
# include <math.h>
#include <c++/vector>
struct ListNode {
    int val;  //当前结点的值
    ListNode *next;  //指向下一个结点的指针
    ListNode(int x) : val(x), next(NULL) {}  //初始化当前结点值为x,指针为空
};
int main(){
    vector<int> nums1;
//    nums1.push_back(2);
//    nums1.push_back(2);
//    nums1.push_back(0);
//    nums1.push_back(2);
    vector<int> nums2;
    nums2.push_back(1);
//    nums2.push_back(3);
//    nums2.push_back(2);
//    nums2.push_back(3);
    int len1 = nums1.size();
    int len2 = nums2.size();
    struct ListNode* l_num = new ListNode(0);
    ListNode* p = l_num;
    int p1 = 0, p2 = 0;
    bool full1 = false, full2 = false;
    if(len1 == 0)
        full1 = true;
    if(len2 == 0)
        full2 = true;
    while(!full1 || !full2){
        if(!full1 && (full2 || nums1[p1] <= nums2[p2])){
            struct ListNode* new_p = new ListNode(nums1[p1]);
            p->next = new_p;
            p = new_p;
            if(p1 == len1 - 1)
                full1 = true;
            else
                p1 ++;
        }else if(!full2 && (full1 || nums1[p1] > nums2[p2])){
            struct ListNode* new_p = new ListNode(nums2[p2]);
            p->next = new_p;
            p = new_p;
            if(p2 == len2 - 1)
                full2 = true;
            else
                p2 ++;
        } else if(full1){
            struct ListNode* new_p = new ListNode(nums2[p2]);
            p->next = new_p;
            p = new_p;
            if(p2 == len2 - 1)
                full2 = true;
            else
                p2 ++;
        } else if(full2){
            struct ListNode* new_p = new ListNode(nums1[p1]);
            p->next = new_p;
            p = new_p;
            if(p1 == len1 - 1)
                full1 = true;
            else
                p1 ++;
        }
    }
    p = l_num->next;
    int len = len1 + len2;
    int count = 0;
    int num1, num2;
    int num3;
    if(len % 2 == 0){
        while(p){
            if(count == len / 2 - 1)
                num1 = p->val;
            if(count == len / 2)
                num2 = p->val;
            p = p->next;
            count ++;
        }
//        cout << (num1 + num2) / 2.0;
        return (num1 + num2) / 2.0;
    } else{
        while(p){
            if(count == len / 2)
                num3 = p->val;
            p = p->next;
            count ++;
        }
//        cout << num3 / 1.0;
        return num3 / 1.0;
    }

    return 0;
}