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# cat file id appsSubmitted appsCompleted appsRunning appsFailed appsKilled ts 5 95255 94881 8 77 289 2019-03-14 15:04:31 6 95263 94883 14 77 289 2019-03-14 15:06:08 7 95318 94941 11 77 289 2019-03-14 15:15:00 8 95318 94941 11 77 289 2019-03-14 15:15:01 9 95324 94947 11 77 289 2019-03-14 15:16:02 10 95326 94950 10 77 289 2019-03-14 15:17:01 11 95334 94955 13 77 289 2019-03-14 15:18:01 12 95337 94961 10 77 289 2019-03-14 15:19:01 13 95341 94966 9 77 289 2019-03-14 15:20:01 14 95341 94967 8 77 289 2019-03-14 15:21:02
1. Find the maximum id
Method One (Use preset values for comparison)
[root@hbhly_60_213 ~]# cat file |tail -n +2|awk -F " " 'BEGIN{max=0}{if($1>max){max=$1}}END{print max}'
14
Method two (use array sort to fetch the first value)
[root@hbhly_60_213 ~]# cat file |tail -n +2|awk -F " " '{number[$1]=$1}END{for(i in number){print number[i]|"sort -nr|head -n 1"}}'
14
2. Find the minimum id
Method One (Use preset values for comparison)
[root@hbhly_60_213 ~]# cat file |tail -n +2|awk -F " " 'BEGIN{min=5}{if($1<min){min=$1}}END{print min}'
5
But this has a flaw: the minimum value must be given in advance, if you use $ 1 to obtain, the obtained value is empty
[root@hbhly_60_213 ~]# cat file |tail -n +2|awk -F " " 'BEGIN{min=$1}{if($1<min){min=$1}}END{print min}'
Method two (use array sort to fetch the first value)
[root@hbhly_60_213 ~]# cat file |tail -n +2|awk -F " " '{number[$1]=$1}END{for(i in number){print number[i]|"sort -n|head -n 1"}}'
5
3. Take out the sum of id
[root@hbhly_60_213 ~]# cat file |tail -n +2|awk -F " " '{sum+=$1}END{print sum}'
95
4. Calculate the average value of id
[root@hbhly_60_213 ~]# cat file |tail -n +2|awk -F " " '{sum+=$1}END{print sum/(NR-1)}'
10.5556