The smallest k number in the array
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topic
Enter n integers to find the smallest K number. For example, enter 4, 5, 1, 6, 2, 7, 3, 8 these 8 numbers, then the smallest 4 numbers are 1,2,3,4.
Ideas
Idea 1:
Use the fast-sorting partition function to initially sort the array, so that the arrays around k-1 are sorted.
Output the first k digits.
Idea 2:
When dealing with massive amounts of data, you can use a multi-set of k elements with the largest number on top to continuously judge whether to update the number in the set.
achieve
class Solution {
public:
int partition(vector<int>& numbers, int left, int right)
{
if(numbers.empty() || left<0 || right>=numbers.size() || left>right)
return -1;
int pivot = numbers[left];
while(left<right)
{
while(left<right && numbers[right]>=pivot)
--right;
numbers[left] = numbers[right];
while(left<right && numbers[left]<=pivot)
++left;
numbers[right] = numbers[left];
}
numbers[left] = pivot;
return left;
}
vector<int> GetLeastNumbers_Solution(vector<int> input, int k) {
vector<int> result;
if(input.empty() || k<=0 || input.size()<k)
return result;
int left = 0;
int right = input.size()-1; //记得是减1
int pindex = partition(input, left, right);
int mark = k-1;
while(pindex!=mark)
{
if(pindex<mark)
{
left = pindex+1;
pindex = partition(input, left, right);
}
else
{
right = pindex-1;
pindex = partition(input, left, right);
}
}
for(int i=0; i<k; ++i)
result.push_back(input[i]);
return result;
}
};