Chapter 5-11 Dictionary merging (40 points) (examine the processing of mixed sorting of numbers and strings)

Dictionary merge. The input uses a string to represent two dictionaries, and the combined dictionary is output. The keys of the dictionary are represented by a letter or number. Note: 1 and '1' are different keywords!

Input format:

Enter the first dictionary string in the first line Enter the second dictionary string in the second line

Output format:

The combined dictionary is output in one line, and the output is in lexicographic order. The ASCII value of "1" is 49, which is greater than 1. When sorting, 1 is first, "1" is next, and the others are the same.

Input example 1:

Here is a set of inputs. E.g:

{1:3,2:5}
{1:5,3:7} 

 

Sample output 1:

The corresponding output is given here. E.g:

{1:8,2:5,3:7}

 

Input example 2:

Here is a set of inputs. E.g:

{"1":3,1:4}
{"a":5,"1":6}

 

Sample output 2:

The corresponding output is given here. E.g:

{1:4,"1":9,"a":5}
第一版（代码死板，不建议参考，见第二版）

# Dictionary merge 
# Author: cnRick 
# Time: 2020-4-10 
dict1 = eval (the INPUT ())
dict2 = eval(input())
keys1 = dict1.keys()
keys2 = dict2.keys()
minLenFlag = 1 if len(dict1) > len(dict2) else 0
if minLenFlag == 0:
    for i in keys1:
        if i in dict2:
            dict2[i] = dict2[i] + dict1[i]
        else:
            dict2[i] = dict1[i]
    keys = list(dict2.keys())
    keys.sort(key = lambda x: ord(x) if type(x)==str else x)
    cnt = 0
    print("{",end="")
    for i in keys:
        if type(i) == int:
            print("{:d}:{:d}".format(i,dict2[i]),end="")
            cnt += 1
        elif type(i) == str:
            print('"{:s}":{:d}'.format(i,dict2[i]),end="")
            cnt += 1
        if cnt != len(dict2):
            print(",",end="")
    print("}",end="")
        
else:
    for i in keys2:
        if i in dict1:
            dict1[i] = dict1[i] + dict2[i]
        else:
            dict1[i] = dict2[i]
    keys = list(dict1.keys())
    keys.sort(key = lambda x: ord(x) if type(x)==str else x)
    cnt = 0
    print("{",end="")
    for i in keys:
        if type(i) == int:
            print("{:d}:{:d}".format(i,dict1[i]),end="")
            cnt += 1
        elif type(i) == str:
            print('"{:s}":{:d}'.format(i,dict1[i]),end="")
            cnt += 1
        if cnt != len(dict1):
            print(",",end="")
    print("}",end="")

second edition

 1 # 字典合并-简化版
 2 # Author: cnRick
 3 # Time  : 2020-4-10
 4 dict1 = eval(input())
 5 dict2 = eval(input())
 6 for key in dict2.keys():
 7     dict1[key] = dict1.get(key,0) + dict2[key]
 8 
 9 items_list = list(dict1.items())
10 items_list.sort(key=lambda item:ord(item[0]) if type(item[0]) == str else item[0])
11 print(str(dict(items_list)).replace(" ","").replace("'",'"'))

Ideas for reference: https://blog.csdn.net/qq_43479432/article/details/105009411