1. seeking plurality intersection list
Input:
"""以a、b、c为实验对象，求a、b、c都同时拥有的元素"""
a = [0,1,2,3,4]
b = [0,2,6]
c = [-1,2,5,8]
# 求多个list的交集：a、b、c同时拥有的元素
r = list(set(a).intersection(b,c))
print('r -->', r) # 输出r --> [2]
2. The list of a plurality of seek and set
Input:
"""以a、b、c为实验对象，求a、b、c的并集"""
a = [0,1,2,3,4]
b = [0,2,6]
c = [-1,2,5,8]
# 求多个list的并集
r = list(set(a).union(b,c))
print('r -->', r) # 输出：r --> [0, 1, 2, 3, 4, 5, 6, 8, -1]
3. A list of the plurality of seek difference (s) set - i.e., retrieve a specific list has an other list elements are not
Input:
"""以a、b、c为实验对象，求 a 中有，但 b 和 c 都没有的元素的并集"""
a = [0,1,2,3,4]
b = [0,2,6]
c = [-1,2,5,8]
# 求特定1个list(a)中有，其他list(b、c)都没有的元素
r = list(set(a).difference(b,c))
print('r -->', r) # 输出：r --> [1, 3, 4]
