File Upload
Overview: Most of the documents are uploaded through a form submitted to the backend server form, therefore, to achieve file upload function, you need to provide a file upload form, but the form requires the following three conditions:
1, form method attribute is set to form post
2, enctype property sheet to form multipart / form-data
3, provided <input type = "file" name = "filename" /> input box file upload
Example code:
<form action="后台路径" method="post" enctype="multipart/form-data" method="post">
<input type="file" name="fileName" />
<input type="submit" value="提交"/>
</form>
SpringMVC in to provide two jar package upload:
commons-fileupload-1.3.2.jar
commons-io.2.5.jar
Example code:
jsp Code:
Add the following code in the configuration file:
Controller write the code:
@RequestMapping("/fileUpload")
public String handlerFormUpload(@RequestParam("name") String name,
@RequestParam("uploadfile") List<MultipartFile> uploadfile,
HttpServletRequest request) {
// determine whether the uploaded file exists
if (!uploadfile.isEmpty() && uploadfile.size() > 0) {
// loop output file upload
for (MultipartFile file : uploadfile) {
// get the original name of the uploaded file
String yuanshiFileName = file.getOriginalFilename();
// set the address directory to save the uploaded file
String driPath = request.getServletContext().getRealPath(
"/upload/");
File filePath = new File(driPath);
// If the address to save the file does not exist, create a directory
if (!filePath.exists()) {
filePath.mkdirs();
}
// use the file name to rename uploaded UUID
String newFilename = name + "_" + UUID.randomUUID() + "_"
+ YuanshiFileName;
try {
file.transferTo(new File(driPath + newFilename));
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace ();
return "error";
}
}
return "success";
} else {
return "error";
}
}
document dowload
