@java Blue Bridge Cup Group B Exercise Basics (30) Q7: special number

@java Blue Bridge Cup Group B Exercise Basics (30) Q7: special number

Keywords: digital loop judge

Resource constraints
Time limit: 1.0s Memory Limit: 512.0MB

Problem Description

153 is a very special number, which is equal to that of cubic and each digit, i.e., 153 = 1 . 1 1 + 5 . 5 5 + 3 . 3 3 All three decimal demand programming to meet this condition.
Output format
　　output three decimal number satisfying the condition in ascending order of each number per line.

Code

public class the Main {
public static void main (String [] args) {
fangFa ();
}
public static void fangFa () {
for (int I = 100; I <1000; I ++) {// find the number of qualifying and outputs
Bai = I int / 100;
int Si =% 100 I / 10;
int GE% I = 10;
IF (I == Bai Bai Bai + Si Si Si + GE GE GE) {
System.out.println (I);
}
}
}
}