To prove safety offer-- stack and queue

Description Title
two stacks to implement a queue, the completion queue Push and Pop operations. Queue elements int.

# -*- coding:utf-8 -*-
class Solution:
    def __init__(self):
        self.stack1 = []
        self.stack2 = []
        
    def push(self, node):
        # write code here
        self.stack1.append(node)
        
    def pop(self):
        # return xx
        if self.stack2 == []:
            while self.stack1:
                tmp = self.stack1.pop()
                self.stack2.append(tmp)
        return self.stack2.pop()

Title Description
Given an array and the size of the sliding window, sliding window to find the maximum value among all values. For example, if the input array size and {2,3,4,2,6,2,5,1} 3 sliding window, then the presence of a total of six sliding window, their maximum values is {4,4,6, 6,6,5}; it has the following six array {2,3,4,2,6,2,5,1} for the sliding window: {[2,3,4], 2,6,2,5 , 1}, {2, [3,4,2], 6,2,5,1}, {2,3, [4,2,6], 2, 5}, {2,3,4 , [2,6,2], 5,1}, {2,3,4,2, [6,2,5], 1}, {2,3,4,2,6, [2,5, 1]}.

# -*- coding:utf-8 -*-
class Solution:
    def maxInWindows(self, num, size):
        # write code here
        length = len(num)
        res = []
        if size < 1 or size > length:
            return []
        for i in range(length-size+1):
            res.append(max([x for x in num[i:i+size]]))
        return res