[Application] the basics of Python (21) Dictionary in the project (to store employee information)

# Recording information of employees: job number, name, title, department, salary 
Source = " 7782, CLARK, MANAGER, SALES, 5000 $ " \
          " 7934, MILLER, SALESMAN, SALES, 3000 $ " \
          " 7369, SMITH, ANALYST , s, 2000 " 


# 1. the number will be $ each employee data segmented (divided into three sets of data) (List type) 
EMP_LIST source.split = ( " $ " )
 Print (EMP_LIST)
 # output: [ '7782, CLARK, MANAGER, SALES, 5000 ',' 7934, MILLER, SALESMAN, SALES, 3000 ',' 7369, SMITH, ANALYST, RESEARCH, 2000 '] 


# statement all_emp used to store all employee information, key: number of employees, value: employee information 
all_emp = {} 

# 2.Employee information stored in the dictionary 
for iin Range (0, len (EMP_LIST)): 

　　# 2.1 in accordance with the division number of each employee information (Type List) 
    Employee = EMP_LIST [I] .split ( " , " ) 

    # 2.2 employee information key value pairs mode storage (Dictionary type) 
    dic_emp = { ' Number ' : Employee [0], ' name ' : Employee [. 1], ' Job ' : Employee [2], ' Dept ' : Employee [. 3], ' the salary ' : Employee [4 ]} 

    # 2.3 storage mode changes again, key as employee number, value, compared with the corresponding employee information (Dictionary type) 
    all_emp [dic_emp [ ' number ']] =dic_emp
 

# 3. Number of employees view employee information in accordance with 
emp_no the INPUT = ( " Please enter the employee number: " )
 IF emp_no in all_emp: 
    emp = all_emp.get (emp_no)
     Print ( " Employee Number: {number}, Name: {name} working: {job}, departments: {dept}, salary: salary {} " .format_map (emp))
 the else :
     Print ( " the employee number does not exist " )