go variables and scope

The figure of the same address 1,2,4

• x:=1Equivalent to first declare a variable x, then the assignment 1;
• x,err=f(1)So consistent is equivalent to the assignment address
• x,err1:=f(4)The statement did not report the error is repeated because the back has a new err1, so the compiler will re-think the statement is behind the variable err1, just in front of the x assignment only, so the address will be the same

3,5 address is not the same

• 3 xx,err:=f(3)is equivalent to declare and assign a new variable xx, the address would become;
• The reason is to address inconsistencies in {5}, related to the scope and go, will give priority to look for within the block, the block can not be found again in order to find the outside