Codeup cemetery - Problem C: hex conversion

Title Description

A length of up to 30 decimal digits nonnegative integer output is converted into a binary number.

Entry

A plurality of sets of data, each of the behavior of a length of not more than 30 decimal nonnegative integer.
(Note that the number is a decimal number 30 may have, instead of the integer 30bits)

Export

Binary number corresponding to each line of output.

Sample input

985
211
1126

Sample Output

1111011001
11010011
10001100110

#include <stdio.h>
#include <string.h>
int main()
{
    char d[32];
    int ans[100];
    while(scanf("%s",d)!=EOF)
    {
        int sum=1,i=0,num[32],t,len=strlen(d);
        for(int j=0; j<len; j++)
            num[j]=d[j]-'0';    //将字符型数字转换为数字
        while(sum)
        {
            sum=0;      //用于进行循环，当所得的数剩1，除以2得0时结束
            for(int j=0; j<len; j++)
            {
                t=num[j]/2;
                sum+=t;
                if(j==len-1)     //如果是此数的最后一位，直接除二取余
                    ans[i++]=num[j]%2;
                else
                    num[j+1]+=(num[j]%2)*10;   //操作后得到的余数加上下一位数
                num[j]=t;    //得到商
            }
        }
        for(int j=i-1; j>=0; j--)  //逆向取余
            printf("%d",ans[j]);
        printf("\n");
    }
    return 0;
}

operation result:

Implementation process:

23 For example, an initial array of num 2 3, num becomes 11 after the for loop, ans [0] = 1; num becomes longer for later cycles 0 5, ans [1] = 1; num becomes longer for later cycles 0 2, ans [2] = 1; num becomes longer for later cycles 0 1, ans [3] = 0; num becomes longer for later cycles 0 0, ans [4] = 1. Finally, reverse output ans array.