*args和**kwargs
* Args is an array of all parameters; ** kwargs parameter is a dictionary, see specific examples:
def test(a,*args,**kwargs):
print a
print args
print kwargs
test(1,2,3,d='4',e=5)
Output:
1
(2, 3)
{'e': 5, 'd': '4'}
Example 2:
def foo(*args, **kwargs):
print ('args = ', args)
print ('kwargs = ', kwargs)
if __name__ == '__main__':
foo(1,2,3,4)
foo(a=1,b=2,c=3)
foo(1,2,3,4, a=1,b=2,c=3)
foo('a', 1, None, a=1, b='2', c=3)
Output:
args = (1, 2, 3, 4)
kwargs = {}
---------------------------------------
args = ()
kwargs = {'a': 1, 'c': 3, 'b': 2}
---------------------------------------
args = (1, 2, 3, 4)
kwargs = {'a': 1, 'c': 3, 'b': 2}
---------------------------------------
args = ('a', 1, None)
kwargs = {'a': 1, 'c': 3, 'b': '2'}
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to sum up
These two parameters are variable in python. * args represents unnamed parameters any more, it is a tuple; ** kwargs represents keyword arguments, it is a dict. And use * args and ** kwargs time, * args parameter must be before ** kwargs, like foo(a=1, b='2', c=3, 1, None )
this call, it will prompt syntax error“SyntaxError: non-keyword arg after keyword arg”