Subnetting exercises -3

Topics requirements:
to achieve the allocation of five departments and the IP address of the server with the 192.168.1.0/24 network, and give corresponding number five sectors are: 55,16,25,8,20

Need to know points:

Jingle :( first big meet after meet small, only allows multiple, less is not allowed and will not allow just good)

First five the number of descending order: 55,25,20,16,8
clear meaning of the questions, here to subnetting, conducted by bit computing.
/ 24: 1,111,111,111,111,111 1,111,111,100,000,000

1. For correlation analysis of 55:
   2 ^ 5 <55, 55 <2 ^ 6
   then: master bit 2 ^ 6 = 64
   network bit 2, bit borrow from the host 2, the suffix changes / 26
   /26: 11111111 11111111 1,111,111,111,000,000

    11000000                    00111111
    00000000                    00000000
    ——————————————————————————————————————
    00000000                    00111111
        0                          63
    前者为与运算               后者为或运算

It is the network address: 192.168.1.0/26
broadcast address: 192.168.1.63/26
available IP address 192.168.1.0/26--192.168.1.62/26

2. For correlation analysis 25:
   2 ^ 4 <25, 2 ^ 5> 25,
   then: master bit 2 ^ 5 = 32
   network bit 3, bit borrow from the host 3, the suffix changes / 27
   /27: 1,111,111,111,111,111 1,111,111,111,100,000
   network address: 192.168.1.64/27
   broadcast address: 192.168.1.95/27
   available IP address 192.168.1.65/27-192.168.1.94/27

3. For correlation analysis of 20:
   2 ^{. 4 <20, 20 <2} 5
   Then: master bit 2 ^ 5 = 32
   network bit 3, bit borrow from the host 3, the suffix changes / 27
   /27: 11111111 1,111,111,111,111,111 11.1 million
   Internet address is: 192.168.1.96/27
   broadcast address: 192.168.1.127/27
   available IP address 192.168.1.97/27-192.168.1.126/27

4. For correlation analysis of 16:
   2 ^ 4 = 16
   then: master bit 2 ^ 5 = 32
   network bit 3, bit borrow from the host 3, the suffix changes / 27
   /27: 1,111,111,111,111,111 1,111,111,111,100,000
   network address : 192.168.1.128/27
   broadcast address is: 192.168.1.159/27
   available IP address 192.168.1.129/27-192.168.1.158/27

5. For correlation analysis of 8:
   2 ^ 3 = 8
   then: master bit 2 ^ 4 = 16
   network 4 bits, 4 bits from the borrow bit host, becomes suffix / 28
   /28: 1,111,111,111,111,111 1,111,111,111,110,000
   network address : 192.168.1.160/28
   broadcast address is: 192.168.1.175/28
   available IP address 192.168.1.161/28-192.168.1.175/28

In summary, as shown below: