Leetcode-119-Pascal's Triangle II

Pascal's Triangle II

 

 

来自 <https://leetcode.com/problems/pascals-triangle-ii/>

Given an index k, return the kth row of the Pascal's triangle.

For example, given k = 3,

Return [1,3,3,1].

Note:

Could you optimize your algorithm to use only O(k) extra space?

题目解读:

给定一个数k,返回杨辉三角中第k行的元素。例如k=3,返回[1,3,3,1]。只能用 O(k) 个额外空间。

解析:

假设在程序开始时就有 O(k) 个空间,由后向前就行添加每行的元素。例如在程序k=5,解析如下图所示



 Java 代码:

    public List<Integer> getRow(int rowIndex) {
        ArrayList<Integer> currentLevel = new ArrayList<Integer>();
        for (int i=0; i<rowIndex+1; i++) {
        	currentLevel.add(i, 1);
        	for(int j=i-1; j>0; j--) {
        		currentLevel.set(j, currentLevel.get(j) + currentLevel.get(j-1));
        	}
        }
        return currentLevel;
    }

 算法性能



 

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转载自logicluo.iteye.com/blog/2238033