C++运算符重载实验

C++运算符重载实验

通过增加新的运算符来提高类的复杂性，在下面已定义好的复数类的基础上，增加重载运算符+，-=，=，/=，++,<<。然后，在主函数中进行测试。操作符重载函数应该被定义为成员函数或友元函数。
#include
using namespace std;
class Complex{
double re, im;
public:
Complex (double r=0, double i=0)
{ re=r; im=i;}
void show();
};
void Complex ::show()
{ cout<<re<<"+"<<im<<“i”<<endl; }
int main()
{
Complex c1(1,2),c2(3,4),c3;
c3=c1+c2; c3.show();
c3-=c1; c3.show();
c3=c1; c3.show();
c3/=c2; c3.show();
c3++; c3.show();
cout<<c1<<endl;
cout<<c2<<endl;
cout<<c3<<endl;
return 0;
}
提示：复数运算法则如下：
加法：(a+bi)+(c+di)=(a+c)+(b+d)i
减法：(a+bi)-(c+di)=(a-c)+(b-d)i
乘法：(a+bi)(c+di)=(ac-bd)+(bc+ad)i
除法：(a+bi)/(c+di)= (ac+bd)/(c^2+d2) +(bc-ad)/(c^2+d2)i

#include<iostream>
using namespace std;
class Complex 
{
	double re, im;
public:
	Complex(double r = 0, double i = 0)
	{
		re = r; im = i;
	}
	Complex operator+(Complex a);
	friend Complex& operator-=(Complex& a, Complex& b);
	Complex& operator*=(Complex& a);
	Complex& operator/=(Complex& a)
	{
		Complex temp = *this;
		this->re =  (temp.re * a.re + temp.im * a.im) / (a.re*a.re + a.im * a.im);
		this->im =  (temp.im * a.re - temp.re * a.im) / (a.re*a.re + a.im * a.im);
		return *this;
	}
	//后置自增
	Complex operator++(int)
	{
		Complex result(*this);
		im++;
		re++;
		return result;
	}
	friend ostream& operator<<(ostream& out, const Complex& cur)
	{
		out << cur.re << "+" << cur.im << "i" << endl;
		return out;
	}
	void show();
};
Complex Complex::operator+(Complex a)
{
	Complex result;
	result.re = this->re + a.re;
	result.im = this->im + a.im;
	return result;
}
Complex& operator-=(Complex& a, Complex& b)
{
	a.im = a.im - b.im;
	a.re = a.re - b.re;
	return a;
}
Complex& Complex::operator*=(Complex& a)
{
	Complex temp = *this;
	this->re = temp.re * a.re - temp.im * a.im;
	this->im = temp.im * a.re + temp.re * a.im;
	return *this;
}
void Complex::show()
{
	cout << re << "+" << im << "i" << endl;
}
int main()
{
	Complex c1(1, 2), c2(3, 4), c3;

	c3 = c1 + c2;  	 c3.show();
	c3 -= c1;    	 c3.show();
	c3 *= c1;   	 c3.show();
	c3 /= c2; 	 c3.show();
	c3++;  		 c3.show();
	cout << c1 << endl;
	cout << c2 << endl;
	cout << c3 << endl;
	return 0;
}