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If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.
Note: If the number is a multiple of both 3 and 5, only count it once.
def solution(number):
sum=0
for val in range(1,number):
if val%3==0 or val%5==0:
sum+=val
print(sum)
if __name__ == '__main__':
solution(21)