题目链接:http://codeforces.com/contest/1096
第一题:
#include<bits/stdc++.h>
using namespace std;
#define debug puts("YES");
#define rep(x,y,z) for(int (x)=(y);(x)<(z);(x)++)
#define ll long long
#define lrt int l,int r,int rt
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define root l,r,rt
#define mst(a,b) memset((a),(b),sizeof(a))
#define pii pair<ll,ll>
#define mk(x,y) make_pair(x,y)
const int maxn =1e5+5;
const int mod=998244353;
const int ub=1e6;
ll powmod(ll x,ll y){ll t; for(t=1;y;y>>=1,x=x*x%mod) if(y&1) t=t*x%mod; return t;}
ll gcd(ll x,ll y){return y?gcd(y,x%y):x;}
int x,y;
int main()
{
int t;scanf("%d",&t);
while(t--)
{
cin>>x>>y;
cout<<x<<" "<<y/x*x<<endl;
}
return 0;
}
第二题:
#include<bits/stdc++.h>
using namespace std;
#define debug puts("YES");
#define rep(x,y,z) for(int (x)=(y);(x)<(z);(x)++)
#define ll long long
#define lrt int l,int r,int rt
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define root l,r,rt
#define mst(a,b) memset((a),(b),sizeof(a))
#define pii pair<ll,ll>
#define mk(x,y) make_pair(x,y)
const int maxn =1e5+5;
const int mod=998244353;
const int ub=1e6;
ll powmod(ll x,ll y){ll t; for(t=1;y;y>>=1,x=x*x%mod) if(y&1) t=t*x%mod; return t;}
ll gcd(ll x,ll y){return y?gcd(y,x%y):x;}
int n;
string s;
int main()
{
cin>>n>>s;
int flag=0;
for(int i=0;i<n-1;i++) if(s[i]!=s[i+1]) flag=1;
if(flag==0)
{
int tmp=n,tmpp=tmp+1;
if(tmp&1) tmpp>>=1;
else tmp>>=1;
cout<<1LL*tmp*tmpp%mod<<endl;
}
else{
if(s[0]==s[n-1])
{
int i=0,j=n-1;
while(s[i+1]==s[i]) i++;
while(s[j]==s[0]) j--;
cout<<1LL*(n-j)*(i+2)%mod<<endl;
}
else
{
int i=0,j=n-1;
while(s[i+1]==s[i]) i++;
while(s[j]==s[j-1]) j--;
int ans=((n-j+1)%mod+mod)%mod+i+1;
ans=(ans+mod)%mod;
cout<<ans<<endl;
}
}
return 0;
}
第三题:
#include<bits/stdc++.h>
using namespace std;
#define debug puts("YES");
#define rep(x,y,z) for(int (x)=(y);(x)<(z);(x)++)
#define ll long long
#define lrt int l,int r,int rt
#define lson l,mid,rt<<1
#define rson mid+1,r,rt<<1|1
#define root l,r,rt
#define mst(a,b) memset((a),(b),sizeof(a))
#define pii pair<ll,ll>
#define mk(x,y) make_pair(x,y)
const int maxn =1e5+5;
const int mod=998244353;
const int ub=1e6;
ll powmod(ll x,ll y){ll t; for(t=1;y;y>>=1,x=x*x%mod) if(y&1) t=t*x%mod; return t;}
ll gcd(ll x,ll y){return y?gcd(y,x%y):x;}
int n,s,x,y;
int d[maxn];
int main()
{
cin>>n>>s;
rep(i,1,n)
{
cin>>x>>y;
d[x]++,d[y]++;
}
int tmp=0;
rep(i,1,n+1) if(d[i]==1) tmp++;
printf("%.9f\n",1.0*s/tmp*2);
return 0;
}