LeetCode 453

题目:Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.

Example:

Input:
[1,2,3]

Output:
3

Explanation:
Only three moves are needed (remember each move increments two elements):

[1,2,3]  =>  [2,3,3]  =>  [3,4,3]  =>  [4,4,4]

标签为easy的竟然编了一个小时还没编出来,然后一看discussion,我去,原来数学东西没搞懂,一个式子就能搞定的东西,我在那里写什么破循环!!!!(我只推出了一个式子,没有推出第二个)

思路:

设加x次,加到最后,每个数都为y

则有: 

sum + (n-1)*x = n*y.........................................................................(式1)

y = min +x...............................................................................................(式2)

得:

x = sum - n* min

以上

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转载自blog.csdn.net/tina_leo/article/details/83003336