Java——HDOJ——1002 A + B Problem II

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 432906    Accepted Submission(s): 84279

 

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2 1 2 112233445566778899 998877665544332211

Sample Output

Case 1: 1 + 2 = 3 Case 2: 112233445566778899 + 998877665544332211 = 1111111111111111110

Author

Ignatius.L

package HUD.dyg;

import java.math.BigInteger;
import java.util.Scanner;
public class Main {
    public static void main(String[] args)
    {
        Scanner input=new Scanner(System.in);
        int n;
        n=input.nextInt();
        for(int i=1;i<=n;i++)
        {
            BigInteger a=input.nextBigInteger();
            BigInteger b=input.nextBigInteger();
            BigInteger c=a.add(b);
            if(i!=1)
                System.out.println();
            System.out.println("Case "+i+":");
            System.out.println(a+" + "+b+" = "+c);
        }
    }

}