Codeforces Round #392 (Div. 2) 758B Blown Garland 【找规律】

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Nothing is eternal in the world, Kostya understood it on the 7-th of January when he saw partially dead four-color garland.

Now he has a goal to replace dead light bulbs, however he doesn't know how many light bulbs for each color are required. It is guaranteed that for each of four colors at least one light is working.

It is known that the garland contains light bulbs of four colors: red, blue, yellow and green. The garland is made as follows: if you take any four consecutive light bulbs then there will not be light bulbs with the same color among them. For example, the garland can look like "RYBGRYBGRY", "YBGRYBGRYBG", "BGRYB", but can not look like "BGRYG", "YBGRYBYGR" or "BGYBGY". Letters denote colors: 'R' — red, 'B' — blue, 'Y' — yellow, 'G' — green.

Using the information that for each color at least one light bulb still works count the number of dead light bulbs of each four colors.

Input

The first and the only line contains the string s (4 ≤ |s| ≤ 100), which describes the garland, thei-th symbol of which describes the color of thei-th light bulb in the order from the beginning of garland:

'R' — the light bulb is red,
'B' — the light bulb is blue,
'Y' — the light bulb is yellow,
'G' — the light bulb is green,
'!' — the light bulb is dead.

The string s can not contain other symbols except those five which were described.

It is guaranteed that in the given string at least once there is each of four letters 'R', 'B', 'Y' and 'G'.

It is guaranteed that the string s is correct garland with some blown light bulbs, it means that for example the line "GRBY!!!B" can not be in the input data.

Output

In the only line print four integers k_r, k_b, k_y, k_g — the number of dead light bulbs of red, blue, yellow and green colors accordingly.

Examples

Input

RYBGRYBGR

Output

0 0 0 0

Input

!RGYB

Output

0 1 0 0

Input

!!!!YGRB

Output

1 1 1 1

Input

!GB!RG!Y!

Output

2 1 1 0

Note

In the first example there are no dead light bulbs.

In the second example it is obvious that one blue bulb is blown, because it could not be light bulbs of other colors on its place according to the statements.

题意：现在有R Y B G 四种颜色的灯泡排成一排。已知每四个相邻的灯泡不会有重复的颜色。现在这排灯泡上有些灯坏掉了，标记为感叹号。请你输出这排灯泡坏之前的情况。

我们可以注意下题目所给的样例：RYBGRYBGRY YBGRYBGRYBG

你会发现，相同字母之间一定会夹着三个字母.。比如：第一组中的R与R之间一定隔着三个字母。

得到这个结论以后，我们会发现，相同字母出现的下标%4都是相同的。

#include<bits/stdc++.h>
using namespace std;
#define LL long long
#define M(a)  memset(a,0,sizeof(a))
char str[105];
int num[5];
int main()
{

    while(~scanf("%s",str))
    {
        M(num);
        int r,b,g,y;
        int len=strlen(str);
        for(int i=0; i<len; i++)
        {
            if(str[i]=='R')
            {
                r=i%4;
            }
            else if(str[i]=='B')
            {
                b=i%4;
            }
            else if(str[i]=='Y')
            {
                y=i%4;
            }
            else if(str[i]=='G')
            {
                g=i%4;
            }
            else
            {
                num[i%4]++;
            }
        }
        printf("%d %d %d %d\n",num[r],num[b],num[y],num[g]);
    }

    return 0;
}

Codeforces Round #392 (Div. 2) 758B Blown Garland 【找规律】

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